Submission #6931447


Source Code Expand

#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <memory>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <vector>
#include <random>
#include <tuple>
#include <iomanip>
#include <cstring>

using namespace std;

typedef long long ll;
//typedef pair<int,int> Pint;
//typedef pair<ll, ll> P;
//typedef pair<ll, pair<ll, ll>> P;
//typedef tuple<int,int,int> T;
typedef vector<ll> vec;
typedef vector<vec> mat;
#define rep(i, n) for(ll i = 0; i < (n); i++)
#define revrep(i, n) for(ll i = (n-1); i >= 0; i--)
#define pb push_back
#define f first
#define s second
//const ll INFL = 1LL << 60;//10^18 = 2^60
const ll INFL = 1LL << 60;
const int INF = 1 << 30;//10^9
ll MOD = 1e9 + 7;
//ll MOD  = 998244353;
vector<ll> dy = {0, 0, 1, -1, 1, 1, -1, -1, 0};
vector<ll> dx = {1, -1, 0, 0, 1, -1, 1, -1, 0};

ll max(ll a, ll b){return (a > b) ? a : b;}
ll min(ll a, ll b){return (a < b) ? a : b;}
ll pow_long(ll x, ll k){
  ll res = 1;
  while(k > 0){
    if(k % 2) res *= x;
    x *= x;
    k /= 2;
  }
  return res;
}
ll pow_mod(ll x, ll k){
  x %= MOD; x += MOD; x %= MOD;
  ll res = 1;
  while(k > 0){
    if(k % 2){
      res *= x; res %= MOD;
    }
    x *= x; x %= MOD;
    k /= 2;
  }
  return res;
}
ll inverse(ll x){return pow_mod(x, MOD - 2);};

//最大公約数
ll gcd(ll a, ll b){
    if(b == 0) return a;
    return gcd(b, a % b);
}

//最小公倍数
ll lcm(ll x, ll y){return x / gcd(x, y) * y;};

//コンビネーション
const int MAXcomb = 200010;
ll fac[MAXcomb], finv[MAXcomb], inv[MAXcomb];
//facはn!,finvは1/n!
//invは逆元
void COMinit(){
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for(int i = 2; i < MAXcomb; i++){
        fac[i] = fac[i-1] * i % MOD;
        inv[i] = MOD - inv[MOD%i] * (MOD/i) % MOD;
        finv[i] = finv[i-1] * inv[i] % MOD;
    }
}
ll comb(int n, int k){
    if(n < k) return 0;
    if(n < 0 || k < 0) return 0;
    return fac[n] * finv[k] % MOD * finv[n-k] % MOD;
}

int main(void){
  int N;
  cin >> N;
  string S;
  cin >> S;
  int a1 = 0, a2 = 0, a3 = 0, a4 = 0;
  rep(i, N){
    if(S[i] == '1') a1++;
    if(S[i] == '2') a2++;
    if(S[i] == '3') a3++;
    if(S[i] == '4') a4++;
  }
  cout << max(max(a1, a2), max(a3, a4)) << " " << min(min(a1, a2), min(a3, a4)) << endl;
}

Submission Info

Submission Time
Task A - センター採点
User shogier
Language C++14 (GCC 5.4.1)
Score 100
Code Size 2534 Byte
Status AC
Exec Time 1 ms
Memory 256 KB

Judge Result

Set Name All
Score / Max Score 100 / 100
Status
AC × 30
Set Name Test Cases
All 00_sample1.txt, 00_sample2.txt, 01_rnd_00.txt, 01_rnd_01.txt, 01_rnd_02.txt, 01_rnd_03.txt, 01_rnd_04.txt, 01_rnd_05.txt, 01_rnd_06.txt, 01_rnd_07.txt, 01_rnd_08.txt, 01_rnd_09.txt, 01_rnd_10.txt, 01_rnd_11.txt, 01_rnd_12.txt, 01_rnd_13.txt, 01_rnd_14.txt, 01_rnd_15.txt, 01_rnd_16.txt, 01_rnd_17.txt, 01_rnd_18.txt, 01_rnd_19.txt, 02_all_1.txt, 02_all_2.txt, 02_all_3.txt, 02_all_4.txt, 03_mini_1.txt, 03_mini_2.txt, 03_mini_3.txt, 03_mini_4.txt
Case Name Status Exec Time Memory
00_sample1.txt AC 1 ms 256 KB
00_sample2.txt AC 1 ms 256 KB
01_rnd_00.txt AC 1 ms 256 KB
01_rnd_01.txt AC 1 ms 256 KB
01_rnd_02.txt AC 1 ms 256 KB
01_rnd_03.txt AC 1 ms 256 KB
01_rnd_04.txt AC 1 ms 256 KB
01_rnd_05.txt AC 1 ms 256 KB
01_rnd_06.txt AC 1 ms 256 KB
01_rnd_07.txt AC 1 ms 256 KB
01_rnd_08.txt AC 1 ms 256 KB
01_rnd_09.txt AC 1 ms 256 KB
01_rnd_10.txt AC 1 ms 256 KB
01_rnd_11.txt AC 1 ms 256 KB
01_rnd_12.txt AC 1 ms 256 KB
01_rnd_13.txt AC 1 ms 256 KB
01_rnd_14.txt AC 1 ms 256 KB
01_rnd_15.txt AC 1 ms 256 KB
01_rnd_16.txt AC 1 ms 256 KB
01_rnd_17.txt AC 1 ms 256 KB
01_rnd_18.txt AC 1 ms 256 KB
01_rnd_19.txt AC 1 ms 256 KB
02_all_1.txt AC 1 ms 256 KB
02_all_2.txt AC 1 ms 256 KB
02_all_3.txt AC 1 ms 256 KB
02_all_4.txt AC 1 ms 256 KB
03_mini_1.txt AC 1 ms 256 KB
03_mini_2.txt AC 1 ms 256 KB
03_mini_3.txt AC 1 ms 256 KB
03_mini_4.txt AC 1 ms 256 KB