Submission #1693874

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Source Code Expand

#include <iostream>
#include <math.h>
using namespace std;
int A, B;
void solve();

int main() {
	cin >> A >> B;
	solve();
	return 0;
}

int one(int n) {
	return abs(n);
}

int five(int n) {
	int f = floor(n/5);
	if (f + one(n - f * 5) < f + 1 + one(n - (f + 1) * 5)) {
		return f + one(n - f * 5);
	}
	else {
		return f + 1 + one(n - (f + 1) * 5);
	}
}

void solve() {
	int t = floor((B-A)/10);
	if (t + five(abs((B - A) - t * 10)) < t + 1 + five(abs((B - A) - (t + 1) * 10))) {
		cout << t + five(abs((B - A) - t * 10)) << endl;
	}
	else {
		cout << t + 1 + five(abs((B - A) - (t + 1) * 10)) << endl;
	}
}

Submission Info

Judge Result